(x^2+2x-63)/(7-x^2)=0

Solution for (x^2+2x-63)/(7-x^2)=0 equation:

(x^2+2x-63)/(7-x^2)=0


Domain of the equation: (7-x^2)!=0

We move all terms containing x to the left, all other terms to the right

-x^2!=-7

x^2!=-7/-

x^2!=√1/0

x!=1

x∈R


We multiply all the terms by the denominator


(x^2+2x-63)=0

We get rid of parentheses

x^2+2x-63=0

a = 1; b = 2; c = -63;
Δ = b2-4ac
Δ = 22-4·1·(-63)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-16}{2*1}=\frac{-18}{2}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+16}{2*1}=\frac{14}{2}
=7
$